Question

(ii) form a quadratic equation whose roots are 3 + root 5 /2 and 3 –root5/2.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

x² -3x + 1 = 0

Step-by-step explanation:

Let roots of quadratic equation are p and q.

Given roots of quadratic equation,

p = (3 + √5)/2

q = (3 - √5)/2

If quadratic equation is ax² + bx + c = 0

So Sum of roots = -b/a

p + q = -b/a

(3 + √5)/2 + (3 - √5)/2 = -b/a

-b/a = (3+3)/2 = 3

Similarly multiplication of roots = c/a

((3 + √5)/2) × ((3 - √5)/2) = c/a

c/a = (3²  (√5)²)/4

c/a = (9 - 5)/4 = 4/4

c/a = 1

Let a = 1

So -b/1 = 3 and b = -3

Similarly c/1 = 1 and c = 1

So quadratic equation is x² -3x +1 = 0.

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