Question

II. Given f(x)= 2x+1 and g(x)= x2 + 2x-1 find

1) f(x) +g(x)

2) f(x).g(x)​

Answer 1

Answer:

OK hope it helps you thanks

Answer 2

$\bf \color{darkorange}{ \underline{ \underline{Given :}}} \\ \\ \rightarrowtail \tt \: f(x) = 2x + 1 \\ \\ \tt \rightarrowtail \: g(x) = {x}^{2} + 2x - 1 \\ \\ \\\bf\color{darkorange}{ \underline{ \underline{To \: \: find :}}} \\ \\ \rightarrowtail \tt \: f(x) + g(x) = {?} \\ \\ \rightarrowtail \tt \: f(x).g(x) = {?} \\ \\\bf\color{brown}{ \underline{ \underline{Step \: \: by \: \: step \: \: explanation \: :}}} \\ \\ \\ \tt \underline{\underline{ f(x) + g(x)}} \\ \\ \tt \rightsquigarrow \: f(x) + g(x) = \: (2x + 1) +( {x}^{2} + 2x - 1) \\ \\ \rightsquigarrow { \green{ \underline {\boxed{\tt \: f(x) + g(x ) = {x}^{2} + 4x}}}} \\ \\ \\ \tt \underline{ \underline{ f(x).g(x)}} \\ \\ \tt \rightsquigarrow f(x).g(x) = (2x + 1)( {x}^{2} + 2x - 1) \\ \\ \rightsquigarrow \tt \: f(x).g(x) = 2 {x}^{3 } + 4 {x}^{2} - \cancel{2x} + {x}^{2} + \cancel{ 2x} - 1 \\ \\ \rightsquigarrow\green{ \underline{ \boxed{ \tt \: f(x).g(x) =2 {x}^{3} + 5 {x}^{2} - 1}}} \\ \\ \\ \tt\colorbox{aqua}{@StayHigh}$