Question

ii)Given log 9 = a, express log 300 and log ✓0.009in terms of a.​

Answer 1

log 3² =a

2log3 =a

log3 = a/2

log 3×100 = log3 + log100 = a/2 +2

log (9/1000)^½

=½ (log 3² - log 10³) = 1/2(a - 3)