Question

ii)
+ H₂SO4caqs
* H269​

Answer 1

Answer:

Correct option is

A

4:1

HCOOHH2SO4concH2O+CO

     a mol                              a mol

H2C2O4H2SO4concH2O+CO+CO2

    b mol                            b mol     b mol

Total number of moles released as gases =a+b+b=a+2b.

The gas produced is collected and on treating with KOH solution, the volume of gas decreases by 61th.

Therefore, b=61(a+2b) ( moles ∞ volume)

ba=4

Hence,  a:b::4:1.