Question

(ii) How many moles of NaCl are present in 20 g of the substance?
[Atomic mass of Na = 23, Cl = 35.5 u]​

Answer 1

Answer:

Molar mass of NaCl = 23+ 35.5 = 58.5

58.5g of NaCl = 1 mole of NaCl

20g of NaCl =

$\frac{20}{58.5} = 0.34$

thus 0.34 moles of NaCl are present in 20g of the substance