Question

(ii)How many oxygen atoms are present in as ample of 150 g vitamin which contains 4.28 moles of oxygen
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Answer 1

Answer:

150 grams of diatomic oxygen: n = 150/32 = 4.69 moles, N = 6.02 X 1023 X 4.69 = 2.82 X 1024 molecules.

Explanation: