Question

(ii) Hydrogen sulphide gas burns in air to give water
and sulphur dioxide. balance​

Answer 1

Answer:

Solution :

Steps to balance chemical equation

Following are the easy steps to balance the equation:

• Step 1: Write the Unbalanced Chemical Equation

Let us consider the given reaction. That is the reaction between Hydrogen sulphide gas burns in air to give water and sulphur dioxide.

H2S + 02 → SO2 + H2O

• Step 2: Write Down Number of Atoms

Write down the number of atoms of each element present on both reactant and product side.

• Step 3: Add Coefficients To Balance the Mass in a Chemical Equation

Note that the coefficients that are to be added must be a whole number and one coefficient added applies to all the atoms present in that one particular molecule.

Example :

• 2 H2O implies 4 hydrogen atoms and 2 oxygen atoms.
• First try to balance the single element oxygen atom and then move to hydrogen
• So here we will first balance simple and then oxygen
• Go by trial and error method. Adding 2 Hydrogen on both sides then it will be 4 on reactants side and on product side 4.
• So 2 H works, 2 hydrogen sulphide, making it 2H20
• The same trial and error procedure is now followed to balance oxygen
• 3 O2 then we have 6 oxygen atoms on the reactant side and also 6 oxygen atoms on the product side.

Hence, The balanced chemical equation is:

2H2S + 302 → 2SO2 + 2H2O

Now the atoms are balanced in both reactant and on the product side.

Hence, the balanced chemical equation for Hydrogen sulphide gas burns in air to give water and sulphur dioxide is given as

2H2S + 3O2 → 2SO2 + 2H2O