Question

ii) If 10.0 mg of Hand 10.0mg Br are mixed with 100.Omg HBr in a 10.0L vessel at
1400K, what is the reaction quotient (Q) for the reaction:
HBr=H(g) + Br(g ) (Eqn-A)​

Answer 1

Answer:

1

Explanation:

Q=[H][Br]/[HBr]

[H]=n/v=weight/mw*volume=10*10^-3/10=10^-3

[Br]=10*10^-3/80*10=10^-3/80

[HBr]=100*10^-3/81*10=10^-2/81

Q=1.01*10^-4