Math, asked by krishnaadittya, 2 months ago

(ii)
If a and B are the zeroes of the polynomial 2x2 - 4x + 5. Form the polynomial where zeros are 1/a^2 , 1/b^2

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Answers

Answered by lisa0001
1

Answer:

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Step-by-step explanation:

(ii)

If a and B are the zeroes of the polynomial 2x2 - 4x + 5. Form the polynomial where zeros are 1/a^2 , 1/b^2

Attachments:
Answered by sritharina4617
4

Answer:

2x  

2

−4x+5

α+β=  

a

−b

​  

=  

2

−(−4)

​  

=  

2

4

​  

=2

αβ=  

a

c

​  

=  

2

5

​  

 

(α  

2

+β  

2

)=(α+β)  

2

−2αβ

=4−5=−1

α

1

​  

+  

β

1

​  

=  

αβ

α+β

​  

=  

2

5

​  

 

2

​  

=  

5

4

​  

 

(α−β)  

2

=(α  

2

+β  

2

)−2αβ

=−1−2(  

2

5

​  

)=−1−5

                     =−6

(α  

3

+β  

3

)=(α+β)(α  

2

+β  

2

−αβ)

=(2)(−1  

2

−5

​  

)

=2(  

2

−7

​  

)=−7

2x  

2

−4x+5

α+β=  

a

−b

​  

=  

2

−(−4)

​  

=  

2

4

​  

=2

αβ=  

a

c

​  

=  

2

5

​  

 

(α  

2

+β  

2

)=(α+β)  

2

−2αβ

=4−5=−1

α

1

​  

+  

β

1

​  

=  

αβ

α+β

​  

=  

2

5

​  

 

2

​  

=  

5

4

​  

 

(α−β)  

2

=(α  

2

+β  

2

)−2αβ

=−1−2(  

2

5

​  

)=−1−5

                     =−6

(α  

3

+β  

3

)=(α+β)(α  

2

+β  

2

−αβ)

=(2)(−1  

2

−5

​  

)

=2(  

2

−7

​  

)=−7

2x  

2

−4x+5

α+β=  

a

−b

​  

=  

2

−(−4)

​  

=  

2

4

​  

=2

αβ=  

a

c

​  

=  

2

5

​  

 

(α  

2

+β  

2

)=(α+β)  

2

−2αβ

=4−5=−1

α

1

​  

+  

β

1

​  

=  

αβ

α+β

​  

=  

2

5

​  

 

2

​  

=  

5

4

​  

 

(α−β)  

2

=(α  

2

+β  

2

)−2αβ

=−1−2(  

2

5

​  

)=−1−5

                     =−6

(α  

3

+β  

3

)=(α+β)(α  

2

+β  

2

−αβ)

=(2)(−1  

2

−5

​  

)

=2(  

2

−7

​  

)=−7

2x  

2

−4x+5

α+β=  

a

−b

​  

=  

2

−(−4)

​  

=  

2

4

​  

=2

αβ=  

a

c

​  

=  

2

5

​  

 

(α  

2

+β  

2

)=(α+β)  

2

−2αβ

=4−5=−1

α

1

​  

+  

β

1

​  

=  

αβ

α+β

​  

=  

2

5

​  

 

2

​  

=  

5

4

​  

 

(α−β)  

2

=(α  

2

+β  

2

)−2αβ

=−1−2(  

2

5

​  

)=−1−5

                     =−6

(α  

3

+β  

3

)=(α+β)(α  

2

+β  

2

−αβ)

=(2)(−1  

2

−5

​  

)

=2(  

2

−7

​  

)=−7

2x  

2

−4x+5

α+β=  

a

−b

​  

=  

2

−(−4)

​  

=  

2

4

​  

=2

αβ=  

a

c

​  

=  

2

5

​  

 

(α  

2

+β  

2

)=(α+β)  

2

−2αβ

=4−5=−1

α

1

​  

+  

β

1

​  

=  

αβ

α+β

​  

=  

2

5

​  

 

2

​  

=  

5

4

​  

 

(α−β)  

2

=(α  

2

+β  

2

)−2αβ

=−1−2(  

2

5

​  

)=−1−5

                     =−6

(α  

3

+β  

3

)=(α+β)(α  

2

+β  

2

−αβ)

=(2)(−1  

2

−5

​  

)

=2(  

2

−7

​  

)=−7

2x  

2

−4x+5

α+β=  

a

−b

​  

=  

2

−(−4)

​  

=  

2

4

​  

=2

αβ=  

a

c

​  

=  

2

5

​  

 

(α  

2

+β  

2

)=(α+β)  

2

−2αβ

=4−5=−1

α

1

​  

+  

β

1

​  

=  

αβ

α+β

​  

=  

2

5

​  

 

2

​  

=  

5

4

​  

 

(α−β)  

2

=(α  

2

+β  

2

)−2αβ

=−1−2(  

2

5

​  

)=−1−5

                     =−6

(α  

3

+β  

3

)=(α+β)(α  

2

+β  

2

−αβ)

=(2)(−1  

2

−5

​  

)

=2(  

2

−7

​  

)=−7

2x  

2

−4x+5

α+β=  

a

−b

​  

=  

2

−(−4)

​  

=  

2

4

​  

=2

αβ=  

a

c

​  

=  

2

5

​  

 

(α  

2

+β  

2

)=(α+β)  

2

−2αβ

=4−5=−1

α

1

​  

+  

β

1

​  

=  

αβ

α+β

​  

=  

2

5

​  

 

2

​  

=  

5

4

​  

 

(α−β)  

2

=(α  

2

+β  

2

)−2αβ

=−1−2(  

2

5

​  

)=−1−5

                     =−6

(α  

3

+β  

3

)=(α+β)(α  

2

+β  

2

−αβ)

=(2)(−1  

2

−5

​  

)

=2(  

2

−7

​  

)=−7

Step-by-step explanation:

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