Question

ii) If p(x) = 2x2 + 4x + 6 is a quadratic polynomial then what is the value of sum of zeroes?

a) 0 b) 1 c) - 2 d) 4 ​

Answer 1

Step-by-step explanation:

Given that:If p(x) = 2x² + 4x + 6 is a quadratic polynomial.

To find:what is the value of sum of zeroes?

a) 0 b) 1 c) - 2 d) 4

Solution:

Tip: If

$a {x}^{2} + bx + c = 0$

is quadratic polynomial,then sum of zeroes is given by

$sum \: of \: zeroes = \frac{ - b}{a}$

write values of a,b,c from give quadratic equation

here

a=2

b=4

c=6

$sum \: of \: zeroes = \frac{ - b}{a} = \frac{ - 4}{2} \\ \\ sum \: of \: zeroes = - 2$

Thus,

Option C is correct.

Hope it helps you.

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Answer 2

SOLUTION

GIVEN

$\sf{p(x) =2 {x}^{2} + 4x + 6 }$

is a quadratic polynomial

TO CHOOSE THE CORRECT OPTION

The value of sum of zeroes

a) 0

b) 1

c) - 2

d) 4

CONCEPT TO BE IMPLEMENTED

$\sf{If \: \alpha \: and \: \beta \: are \: zeroes \: of \: a \: quadratic \: polynomial }$

$\sf{p(x) = a {x}^{2} + bx + c }$

Then

Sum of the zeroes

$= \displaystyle \sf{ \alpha + \beta = - \frac{b}{a} }$

Product of the Zeros

$= \displaystyle \sf{ \alpha \beta = \frac{c}{a} }$

EVALUATION

Here the given polynomial is

$\sf{p(x) =2 {x}^{2} + 4x + 6 }$

Now Comparing with the general polynomial

$\sf{p(x) = a {x}^{2} + bx + c }$

We get a = 2 , b = 4 , c = 6

Hence the sum of the zeroes of the polynomial

$= \displaystyle \sf{ - \frac{b}{a} }$

$= \displaystyle \sf{ - \frac{4}{2} }$

$= - 2$

FINAL ANSWER

The correct option is

(b) - 2

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