Question

(ii) If p(y) = y2 - 2 y + 1 then find p (2).​

Answer 1

Answer:

Given p(y) = y^2 - 2y + 1

Then p(2) = 2^2 - 2(2) +1

               = 4 -4 + 1

               = 0+1

               =1

Hence P(2) = 1

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