Question

(ii) If sec A = cosec A and 0° < A < 90°,
state the value of A.​

Answer 1

Step-by-step explanation:

$\sec(a) = \csc(a) \\ \sec(a) = \sec( {90}^{o} - a ) \\ a = {90}^{o} - a \\ a + a = {90}^{o} \\ 2a = {90}^{o} \\ a = {45}^{o}$