(ii) If sin A= 3,then the value of (9 cot²A+9) is
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Answer:
answer is 17.
Step-by-step explanation:
sin A = 3 , then cos A = -2√2
tan A = sin A / cos A
= 3 / -2√2
cot A = 1 / tan A = 1 / (3 / -2√2) = -2√2 / 3
cot² A = ( -2√2 / 3)²
= ( -2√2)² / 3²
= (-2)²× (√2)² / 9
= 4 × 2 / 9
= 8 / 9
9 cot² A + 9 = (9 × 8 / 9) + 9
= 8 + 9 = 17
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