Question

(ii) If the distance between the two bodies is tripled, how will the Gravitational force
between them change?​

Answer 1

Answer -

We know -

$\implies$$\boxed{\sf{F = \frac{G m_1 m_2 }{ {r}^{2} }}}$

where

$\longrightarrow$F is force of attraction b/w bodies.

$\longrightarrow$$m_1$ and $m_2$ are the mass of bodies.

$\longrightarrow$r is the distance between them.

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Let the Gravitatinal force when distance is tripled be F'

When the distance is tripled , new distacne between them = 3r

Substituting the value -

$\implies$$\sf F' = \frac{G m_1 m_2 }{ ({3r})^{2} }$

$\implies$$\sf F' = \frac{G m_1 m_2 }{ {9 r^2 }}$

$\implies$$\sf F' = \frac{1}{9} F$

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The gravitational force is reduced to 1/9 th time when the distance between them is tripled.

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Additional information -

Value of G :

$G = 6.67 \times 10^{-11} Nm^2 kg^{-2}$

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Newton's law of Gravitation - The magnitude and direction of gravitational force between two particles are given by universal law of Gravitation.

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Universal law of Gravitation - The force of attraction between any two particles is directly proportional to product of masses of particles and is inversely proportional to the square of distance between them.

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Thanks