(ii) If the zeroes of the quadratic polynomial x2 + ( a +1)x + b are 2 and -3, then
(a) a = -7, b = -1 (b) a = 5,5
a = 2, b = -6 Da = 0, b = -6
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x^2+(a+1) x+ b is the quadratic polynomial.
2 and −3 are the zeros of the quadratic polynomial.
Thus, 2+(−3)= 1 - ( a + 1 ) \ 1
=> 1 (a+1) =1
=>a+1=1
=>a=0
Also, 2×(−3)=b
=>b=−6
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