Question

ii. In a ABC. D and E are points on the side the sides AB and AC respectively such that
DE BC. IfAD= 2.4cm. AE=3.2cm, DE=2cm and BC=5cm, find the BD and CE.
In AABC​

Answer 1

Answer:

BD=3.6cm and CE=4.8cm

Step-by-step explanation:

If a line is drawn parallel to one side of a triangle to intersect the

other two sides in distinct points, the other two sides are divided in the same ratio.

As DE∥BC 

∠ADE=∠ABC

∠AED=∠ACB

So by AAA △AED∼△ACB

Hence ACAE=CBED

∴AC3.2=52

⇒AC=8cm

AC=8cm=AE+EC=3.2+EC

EC=8−3.2=4.8cm

Also ABAD=CBED

∴AB2.4=52

AB=6cm=AD+DB=2.4+DB

⇒DB=3.6cm

So BD=3.6cm and CE=4.8cm