Question

ii) In a circle with center 'O', OM AB = 3cm , AM = 4 cm,them find OA- ?​

Answer 1

Answer:

5cm

 Given o is the center of circle ,OM=3 cm and AB=8 cm

Join O to A and B

In figure OM show that the perpendicular from center O on cord AB

WE know that  Perpendicular from the Center of a Circle to a Chord Bisects the Chord.

Then AM=BM

So AM=BM=2AB=28=4cm

ΔAOM

(AO)2=(AM)2+(OM)2=(4)2+(3)2=16+9=25

⇒AO=5cm

Then AO is the radius of circle is 5 cm