Question

(ii) In a game of chance,a spinning arrow comes to rest at one of the numbers
15, 20, 25, 30, 35, 40, 45, 50. All these are equally likely outcomes. What is
the probability that it will rest at (a) an even number (b) at a number
divisible by 5 (c) at a number divisible by 3 (d) at a prime number.
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Answer 1

this is the required solution to your answer

Answer 2

Hey!!!
(a) Favourable outcomes= 4(20,30,40and 50)
Total outcomes=8
Probability= Favourable outcomes/total outcomes
P =4/8
=1/2

(b) favourable outcomes=8( 15,20,25,30,35,40,45,50)
So, P= favourable outcomes/total outcomes
P= 8/8
P= 1

(c) here,
Favourable outcomes =3(15,30,45)
So, P= favourable outcomes/total outcomes
P=3/8

(d) here,
Favourable outcomes =0
So, P=favourable outcomes/total outcomes
P= 0/8
P=0

I hope it helps!!
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