(ii)In a solution, 40g NaOH is dissolved in 500 ml water. Calculate its molarity and normality.
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Answer:
2M. , 2.1m
Explanation:
no.of mol = 40/40 = 1mol
volume of solution = (500/1000)L
= (1/2)L
molarity of solution = no.of mol/volume of solution in litres
= 1/(1/2)M
= 2M
wt.of solution =( 500ml)×(1g/ml)
= 500g
wt.of solvent = (500-40)g
= 460g
molality = no.ofmol. /wt.of solvent in Kg
=( 1/460)×1000 = 100/46= 50/23 = 2.1m
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