(ii) In an isosceles triangle each base angle is 30° greater than the vertical angle. Find the measure
of all the three angles.
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Question :
In an isosceles triangle each base angle is 30° greater than the vertical angle. Find the measure
of all the three angles
Solution :
Let us consider angle a be x , so angle b = x+30 and angle c = x+30
But we know that angle sum property of traingle is 180
So , ∠A+∠B+∠C =180
putting value of ∠A , ∠B, ∠C
So we will get
x+x+30+x+30=180
3x+60=180
3x=180-60
3x= 120
x=120/3
x=40
So ∠A = 40
∠B=70
∠C=70
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