(ii) In right-angled triangle PQR, if angleP=60°, angleR=30° and PR = 12, then find the values of PQ and QR.
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From the given informations it is clear that PQR is an isisceles right triangle with QR as hypotenuse. (Since angle Q=angleR= 45°, the third angleP = 180-(45+45)=90 and alsoPR = PQ
If PR = PQ = a then QR = √2.a= 10 cm
So a = 10/√2 cm
So area of triangle PQR = (1/2)(PR)(PQ)
= (1/2)(10/√2)(10/√2)= 100/4 = 25 cm^2.
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