Question

(ii) In the figure, circle with centre D touches the sides
of angle ACB at A and B as shown. If angle ACB=52°,
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then find the measure of angle ADB.​

Answer 1

Answer:

angle ADB=128°

Step-by-step explanation:

ABCD is a quadrilateral

and, sum of all angles of a quadrilateral is 360°

ADB+DBC+BCA+CAD=360°

ADB+90°+52°+90°=360° (Angle DBC= AngleCAD= 90° because it is a tangent)

ADB+238°=360°

ADB=128°

Answer 2

Answer:

ADB = 128

Step-by-step explanation:

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