Question

ii) In Triangle PQR, point S is the midpoint of side QR. If PQ = 11, PR = 17, PS = 13, find QR , QR.​

Answer 1

In ∆PQR, point S is the midpoint of side QR. [Given]
∴ seg PS is the median.

∴ PQ2 + PR2 = 2 PS2 + 2 SR2

112 + 172 = 2 (13)2 + 2 SR2
∴ 121 + 289 = 2 (169)+ 2 SR2
∴ 410 = 338+ 2 SR2
∴ 2 SR2 = 410 – 338
∴ 2 SR2 = 72
∴ SR2 = 72/2 = 36
∴ SR = √ 36
[Taking square root of both sides]
= 6 units Now, QR = 2 SR [S is the midpoint of QR]
= 2 × 6
QR=12 units