Math, asked by IshaKumari55, 9 months ago

ii) It is given that n(E) = 40, n(P) = 18, n(Q) = 20 and
n(
PQ) = 7. Find (a) n(Pu Q), (b) n(P' U Q').

Answers

Answered by gramlesarang
2

Answer:

a)18+20-7=31.

b)40-7=33

Answered by SASHANKSAHIL
8

Answer:

i) n(P U Q)=31

ii) n(P' U Q')=33

Step-by-step explanation:

given is,

n(U) = 40, n(P) = 18, n(Q) = 20 and

n(P intersection Q)=7

so,

we have the formula,

i) n(P U Q)= n(P)+n(Q)-n(P intersection Q)

so on substituting the value we get,

n(P U Q)= 18+20-7

n(P U Q)=31

ii) n(P' U Q')=n(U)-n(P intersection Q)

so on substituting value we get,

n(P' U Q')=40-7

n(P' U Q')=33

Here I have taken n(U) instead of n(E), because we are taught U(Universal) instead of E, well both are same so no need to worry, its correct only you just have to replace U with E.

Hope You May Get It

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Thank You...

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