ii) It is given that n(E) = 40, n(P) = 18, n(Q) = 20 and
n(
PQ) = 7. Find (a) n(Pu Q), (b) n(P' U Q').
Answers
Answered by
2
Answer:
a)18+20-7=31.
b)40-7=33
Answered by
8
Answer:
i) n(P U Q)=31
ii) n(P' U Q')=33
Step-by-step explanation:
given is,
n(U) = 40, n(P) = 18, n(Q) = 20 and
n(P intersection Q)=7
so,
we have the formula,
i) n(P U Q)= n(P)+n(Q)-n(P intersection Q)
so on substituting the value we get,
n(P U Q)= 18+20-7
n(P U Q)=31
ii) n(P' U Q')=n(U)-n(P intersection Q)
so on substituting value we get,
n(P' U Q')=40-7
n(P' U Q')=33
Here I have taken n(U) instead of n(E), because we are taught U(Universal) instead of E, well both are same so no need to worry, its correct only you just have to replace U with E.
Hope You May Get It
Mark as brainliests too
Thank You...
Similar questions