Question

ii)
k²x2 – 2(k-1) x + 4 = 0​

Answer 1

Answer:

2k×k-2(k-1)x+4=0

2k×k-2kx-2x+4=0

2k(k-2x)-2(x+2)=0

2k+(k-2x)=2(x-2)

k+(k-2x)=(x-2)

(k-2x)=(x-2)/k