Question

(ii) Let's find 8xy (x2 +y) when (x + y) = 5 and (x-y) = 1​

Answer 1

Answer:

528..

Step-by-step explanation:

Let's find out X and Y

The equation though formed are:

x = 5 - y ...(1)

x = 1 + y ...(2)

Hence,

5 - y = 1 + y

5 - 1 = y + y

4 = 2y

Y = 2

If y = 2 then,

x + y = 5

x + 2 = 5

x = 5 - 2

x = 3

Hence,

=8 × 3 × 2 ( 3^2 + 2 )

=48 ( 9 + 2 )

= 48 × 11

= 528