(ii)let x be a +ve integer suh that unit digit of x is prime and product of all digits of x is also prime.How many such integers are possible
(iii)number of real roots in x^4+(2-x)^4=34
rajusetu:
sir i will club questions but increase numbere of points.Is it okay?
i will incresse up to 30-40 etc
there is a mistake in (ii)
sir x is a 4digit number.
the answer is 4
please reply
it was a silly mistake by me
sorry
sorry sir
sir x is a 4digit number.
Answers
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x = positive integer. it is not said that x is prime.
units digit of x is prime, so units digit is one of 2, 3, 5, 7.
product of digits of x is prime. Only way it can happen is that all other digits of x are all equal to 1. Then the number can be
2, 3, 5, 7, 12, 13, 15, 17, 112, 113, 115, 117, 11112, 1113, 1115, 1117, ..
111112, 111113, 111115, 111117, ....
So the number such integers is infinite.
================================
the number of roots of
x^4 + (2 - x)^4 = 34
expand the polynomial and simply to get
P(x) = x^4 - 4 x^3 + 12 x^2 - 16 x - 9 = 0
P(-x) = (-x)^4 - 4 (-x)^3 + 12 (-x)^2 - 16 (-x) -9 = 0
Descartes rule. It gives an upper bound on the number of positive, and negative real roots. It does not necessarily give the exact number of real roots.
coefficients in the polynomial are P(x) : +1, -4, +12, -16, -9
Sign of the coefficients changes plus to minus and minus to plus, three times as we move from left to right. So MAXimum possible real roots are 3. There may be less than that.
Coefficients of P(-x) = +1, +4, +12 , +16, -9
there is only one change in the sign, from +16 to -9. So there is a MAXimum of one negative real root.
Maximum possible real roots are 3+1 = 4. But it is possible that there are less number of real roots. Minimum number of imaginary roots are 0. It can be possibly more than 0, ie., 2 also.
If there are rational roots, they are possibly 1, -1, +3, -3, +9, or -9.
Trying them , P(x) is not 0. There are no rational roots to this polynomial.
==================================
By examining the polynomial, and trying we get that
P(x) = (x^2 - 2x -1) (x^2 - 2x - 9)
the first quadratic expression has real roots : 1 + √2, 1 - √2
the second quadratic expression has imaginary roots: 1 + 2√2 i, 1 - 2√2 i
Actual number of real roots is 2.
=====================================
hands of clock
hour hand moves 360 degrees in 12 hours. It moves 18 degrees in 18/360 * 12 = 3/5 hours = 36 minutes.
Minutes hand moves 360 degrees in 1 hour. So it moves 6 degrees in one minute. SO it moves 36 * 6 = 216 degrees.
units digit of x is prime, so units digit is one of 2, 3, 5, 7.
product of digits of x is prime. Only way it can happen is that all other digits of x are all equal to 1. Then the number can be
2, 3, 5, 7, 12, 13, 15, 17, 112, 113, 115, 117, 11112, 1113, 1115, 1117, ..
111112, 111113, 111115, 111117, ....
So the number such integers is infinite.
================================
the number of roots of
x^4 + (2 - x)^4 = 34
expand the polynomial and simply to get
P(x) = x^4 - 4 x^3 + 12 x^2 - 16 x - 9 = 0
P(-x) = (-x)^4 - 4 (-x)^3 + 12 (-x)^2 - 16 (-x) -9 = 0
Descartes rule. It gives an upper bound on the number of positive, and negative real roots. It does not necessarily give the exact number of real roots.
coefficients in the polynomial are P(x) : +1, -4, +12, -16, -9
Sign of the coefficients changes plus to minus and minus to plus, three times as we move from left to right. So MAXimum possible real roots are 3. There may be less than that.
Coefficients of P(-x) = +1, +4, +12 , +16, -9
there is only one change in the sign, from +16 to -9. So there is a MAXimum of one negative real root.
Maximum possible real roots are 3+1 = 4. But it is possible that there are less number of real roots. Minimum number of imaginary roots are 0. It can be possibly more than 0, ie., 2 also.
If there are rational roots, they are possibly 1, -1, +3, -3, +9, or -9.
Trying them , P(x) is not 0. There are no rational roots to this polynomial.
==================================
By examining the polynomial, and trying we get that
P(x) = (x^2 - 2x -1) (x^2 - 2x - 9)
the first quadratic expression has real roots : 1 + √2, 1 - √2
the second quadratic expression has imaginary roots: 1 + 2√2 i, 1 - 2√2 i
Actual number of real roots is 2.
=====================================
hands of clock
hour hand moves 360 degrees in 12 hours. It moves 18 degrees in 18/360 * 12 = 3/5 hours = 36 minutes.
Minutes hand moves 360 degrees in 1 hour. So it moves 6 degrees in one minute. SO it moves 36 * 6 = 216 degrees.
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but answer was 4 roots were possibler
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