ii) ΔLMN with length m<L = 50ᵒ ; m<M= 70ᵒ; m<N=60ᵒ .
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Answered by
1
Step-by-step explanation:
m<L = 50ᵒ ; m<M= 70ᵒ; m<N=60ᵒ .
m<L + m<M + m<N = 180ᵒ .
This triangle is possible as sum of
angles is supplementary.
LN is the longest side and MN is the smallest side.
Answered by
1
Step-by-step explanation:
In ∆LMN
√L+√M+√N=180°
60°+50°+√N=180°
√N=70°
Now
∆LMN~∆PQR
•••√R=√N
=√N=70°
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