Question

(ii) log3 x – log3 2 = 1 slove for x logarithms
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Answer 1

ǫᴜᴇsᴛɪᴏɴ →

log3 x – log3 2 = 1 slove for x logarithms

ᴀɴsᴡᴇʀ →

Let us solve for x,

$\longmapsto\tt{log³x=1+log³2}$

=log³3+2 [Since, 1 can be written as log³3=1]

$\longmapsto\tt{=llog(3×2)}$

$\longmapsto\tt{log³6}$

$\longmapsto\tt{∴x=6}$