Question

(ii) logx 2 + logx 4 + logx 64 = 9

Answer 1

Answer:

x = 2

Step-by-step explanation:

log(xy) = log(x) + log(y)

~~~~~~~~

$log_{x}$ (2×2²×$2^{6}$ ) = $log_{x}$ $2^{9}$ = 9×$log_{x}$ 2

9 × $log_{x}$ 2 = 9 ===> $log_{x}$ 2 = 1 ===> $x^{1}$ = 2 ===> x = 2