(ii) Lt{(1+x)^n – 1}/x.
x →0.
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When x => 0
(ß + x)^n = ß + nx
Similarly;
Lim {(1 + x)^n - 1}/x
x=>0
= (1 + nx - 1)/x
= nx/x
= n
Thus, the result is equal to n
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