Question

II n (AUB)= 30, (ANB) = 10 find n(A) = n(B)​

Answer 1

Answer:

n(A)=20 and n(B)=20

Step-by-step explanation:

n(AUB) = n(A) + n(B) - n(AnB)

30 = 20+20-10

30 = 40-10

30 = 30

Answer 2

Answer:

let , n(A) = x = n(B)

n(AUB) = n(A) + n(B) - n(A intersection B)

30= 2x - n(A intersection B )

30= 2x -10

40 = 2x

20 = x

n(A) = 20 , n(B) = 20

This is your answer , I hope it will help you dear friend.