Question

(ii) On 1st January 2016, Sanika decides to save 10, 11 on second day, 10
on third day. If she decides to save like this, then on 31st December 2012
what would be her total savings?​

Answer 1

Answer:

It would be 2016 not 2012

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Answer 2

Step-by-step explanation:

10,11,13

d=1,a=10,n=31

because 2016 is a leap year

sn=n/2[2a+(n-1)d]

s31=31/2[2×10+(31-1)1]

s31=31[10+30]

s31=31×40

s31=1240

Sanikas total savings is rs 1240