Math, asked by mehaksaini9, 6 months ago

II (P),
(3 - d)2 + (3)2 + (3 + d)2 = 35​

Answers

Answered by rahulchaudhary14
0

Step-by-step explanation:

(3-d)^2+(3)^2+(3+D)^2=35

using (a-b)^2=a^2+b^2-2ab,. (a+b)^2=a^2+b^2+2ab

=(3^2+d^2-2×3×d)+9+(3^2+d^2+2×3×d)=35

=(9+d^2-6d)+9+(9+d^2+6d)=35

=9+d^2-6d+9+9+d^2+6d=35

=27+2d^2=35

=2d^2=35-27

=2d^2=8

=d^2=8/2=4

=d =√4=2. answer.

Similar questions