(ii) p(x) = 2x2 + k + 2
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Apply remainder theorem
=>x - 1 =0
=> x = 1
According to remainder theorem p(1) = 0 we get
Plug x = 1 we get
p(1) = 2(1)2 + k(1) + √2
p(1) =2 + k + √2
0 = 2 + √2 + k
-2 - √2 = k
- (2 + √2) = k
Answer is k = - (2 + √2)
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