(ii) PQRS is cyclic and Q-R-T. IF ZOPS = 110°, QRS=x and SRT =y,
then find the values of x and y.
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Answer:
QPS=110°(Given)
therefore QPS+QRS=180° (In a cyclic quadrilateral opposite angles add up to 180°)
110°+QRS=180°
QRS=180°-110°
QRS=70°
Now for SRT
SRT=QPS (In a cyclic quadrilateral exterior angle is equal to interior opposite angle)
therefore SRT=110°
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