Question

ii. Prove that 5-7√ is irrational.​

Answer 1

Answer:

Step-by-step explanation:

I HAVE ATTACHED THE SOLUTION..

DON ‘T MIND IZ FROM GOOGLE

HOPE IT HELPS...

PLEASE MARK BRAINLIEST..

Answer 2

Answer:

we need to prove 5 -$\sqrt7$ as irrational

Step-by-step explanation:

let us assume on the contrary that 5- $\sqrt7$ is RATIONAL

Then acc to defination

5-$\sqrt7$= p/q [ where q $\neq$0, and  'p' and 'q' are co-prime integers]

On squaring both sides

$(5-\sqrt7) ^{2}$= $p^{2}$/$q^{2}$

= 25 + 7 - 10$\sqrt7$ =$p^{2}$/$q^{2}$

= 32 - 10$\sqrt7$=$p^{2}$/$q^{2}$

=  - 10$\sqrt7$ = $p^{2}$-32$q^{2}$/$q^{2}$

=$\sqrt7$= 32$q^{2}$-$p^{2}$/10$q^{2}$

here p and q are rational no

= $\sqrt7$ is RATIONAL

BUT

It CONTRADICTS the fact that $\sqrt7$ is IRRATIONAL

therefore, Our assumption goes WRONG

so, 5-$\sqrt7$  is IRRATIONAL

                                                Hence proved

pls mark brainliest if helpful