Physics, asked by ponnamvaishnavi489, 6 hours ago

II. Read the following and answers the given questions from (6) to (10):

A concave mirror forms image of an object thrice in its size on a screen. Magnification of a mirror gives

information about the size of the image relative to the object. It is defined as the ratio of size of image to the size of object. It is represented by m.

m = Size of image/Size of object

Sign of magnification by mirror gives the information about the nature of the image produce by it.

6. The nature of formed image is

(a) Real and inverted

(c) Virtual, and enlarged

(b) Virtual and erect

(d) None of these

7. If the object x distance from the pole of mirror, then image distance from the pole is.

(a)-2x

(b)-3x

(c)-4x

(d)-x

8. If the radius of curvature of mirror is R, then the relation between object distance, image distance and focal length of the mirror is.

(d) None

9. When an object is placed at infinity then the nature of image will be.

(a) real, inverted, highly diminished

(b) virtual, inverted, diminished

(c) virtual, inverted, infinitely large

(d) real, erect and smaller

5 An object is placed at the centre of curvature of a concave mirror. The distance between its image and the pole is

(a) equal of f

(c) equal of 2f

(b) between fand 2f

(d) greater than 2f​

Answers

Answered by umangkumar20
0

Answer:

Given

Object distance, u=24cm

Image distance, v=16cm

From mirror formula

f

1

=

v

1

+

u

1

f

1

=−

16

1

24

1

=−(

16×24

24+16

)

24

10

f=9.6cm= focal length

Radius of cuvature R=2f

=2×−9.6

=−19.2cm

magnification, m=−

u

v

=−

−24

−16

m=−

3

2

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