Question

II. Ronil runs around a square field of side 85 m. Kashif runs around a rectangular field with length 120 m and breadth 72m. Who covers more distance.
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Answer 1

Given:-

• Length of the sides of Square = 85m.

• Length of Rectanglular field = 120m.

• Breadth of Rectangular field = 72m

To Find:-

• Who Covers more Distance?

Formulae used:-

• Perimeter of Square = 4 × Side

• Perimeter of Rectangle = 2 ( L + B )

Now,

→ Perimeter of Square = 4 × Side

→ Perimeter of Square = 4 × 85

→ Perimeter of Square = 340m

So, The Distance Covered by Ronit is 340m

Now, Again

→ Perimeter of Rectangle = 2 ( L + B )

→ Perimeter of Rectangle = 2 ( 120 + 72 )

→ Perimeter of Rectangle = 2 ( 192) → 384m.

So, The Distance Covered by Kashif is 384m.

Hence, The Distance Covered by Kashif is more by 44m.

Answer 2

Answer:

$\setlength{\unitlength}{1.3cm}\begin{picture}(20,2)\thicklines\put(7.3,2){\sf{\large{72 m}}}\put(9.2,0.7){\sf{\large{120 m}}}\put(8,1){\line(1,0){3}}\put(8,1){\line(0,2){2}}\put(11,1){\line(0,3){2}}\put(8,3){\line(3,0){3}}\put(14.1,1.6){\sf{\large{85 m}}}\put(12.7,0.7){\sf{\large{85 m}}}\put(12,1){\line(1,0){2}}\put(12,1){\line(0,2){1.5}}\put(14,1){\line(0,3){1.5}}\put(12,2.5){\line(3,0){2}}\put(8.3,1.8){\bf Rectangular Field}\put(12.1,1.6){\bf Square Field}\end{picture}$

$\underline{\bigstar\:\textsf{Distance covered by Ronil :}}$

$:\implies\sf Ronil=Perimeter\:of\:Square\\\\\\:\implies\sf Ronil=4 \times Side\\\\\\:\implies\sf Ronil=4 \times 85\:m\\\\\\:\implies\sf Ronil = 340\:m$

$\rule{180}{1.5}$

$\underline{\bigstar\:\textsf{Distance covered by Kashif :}}$

$:\implies\sf Kashif=Perimeter\:of\:Rectangle\\\\\\:\implies\sf Kashif=2(Length+Breadth)\\\\\\:\implies\sf Kashif=2(120\:m+72\:m)\\\\\\:\implies\sf Kashif = 2 \times 192\:m\\\\\\:\implies\sf Kashif = 384\:m$

⠀

$\therefore\:\underline{\textsf{\textbf{Kashif} covered more distance by 44 m}}$