Math, asked by huzaifa7529, 5 months ago

(ii) sec^4A - tan^4 A = 1 + 2 tan^2A​

Answers

Answered by Anonymous
5

Answer:

sec^4A - tan^4A

(sec^2A)^2 - (tan^2A)^2

(sec^2A + tan^2A) (sec^2A - tan^2A)

because (a^2 - b^2) = (a + b) (a - b)

so, (sec^A + tan^2A).1

(1 + tan^2A + tan^2A)

(1 + 2tan^2A).

Step-by-step explanation:

#Hope you have satisfied with this answer.

Answered by Anonymous
3

Answer:

sec^4A - tan^4A

(sec^2A)^2 - (tan^2A)^2

(sec^2A + tan^2A) (sec^2A - tan^2A)

because (a^2 - b^2) = (a + b) (a - b)

so, (sec^A + tan^2A).1

(1 + tan^2A + tan^2A)

(1 + 2tan^2A).

Step-by-step explanation:

#Hope you have satisfied with this answer.

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