Question

II sectheta - tantheta =1/3 then find seco + tano
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Answer 1

Answer:

3

Step-by-step explanation:

secA + tanA = 1/3

multiplying both sides by (secA + tanA)

(secA+tanA)(secA−tanA) =(1/3) (secA−tanA)

(secA)^2−(tanA)^2 = (1/3) (secA−tanA)

1 = (1/3) (secA−tanA) since, (secA)^2−(tanA)^2 = 1

so (secA−tanA) = 3

hope you got it

Answer 2

Answer:

3

Step-by-step explanation:

secA + tanA = 1/3

multiplying both sides by (secA + tanA)

(secA+tanA)(secA−tanA) =(1/3) (secA−tanA)

(secA)^2−(tanA)^2 = (1/3) (secA−tanA)

1 = (1/3) (secA−tanA) since, (secA)^2−(tanA)^2 = 1

so (secA−tanA) = 3

hope you got it