Math, asked by aartirajput1431, 6 months ago

(ii) sin 0(1+tan 0) + cos 0 (1 + cot 0) = (sec 0 + cosec )

Answers

Answered by jatinsharma12
8

Step-by-step explanation:

by taking LHS

=sin0(1+sin0/cos0)+cos0(1+cos0/sin0)

=sin0{(cos0+sin0)/cos0}+cos0{(sin0+cos0)/sin0}

=sin0/cos0(cos0+sin0) + cos0/sin0(cos0+sin0)

=(cos0+sin0){sin0/cos0+cos0/sin0}

=(cos0+sin0){(sin²0+cos²0)/(cos0sin0)}

=(cos0+sin0){1/cos0sin0}

=cos0/cos0sin0 + sin0/cos0sin0

=1/sin0+1/cos0

=cosec0+sec0

LHS = RHS

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