Question

(ii) sin 60° cos 30° - cos 60° sin 30°
(iii) cos 60° cos 30° + sin 60° sin 30°
​

Answer 1

$\huge\underline{\overline{\mid\star{\sf{\pink{ANSWER}}\star\mid}}}$

(ii)sin 60° cos 30° - cos 60° sin 30°

= sin(60⁰-30⁰)

= sin30⁰

= 1/2

[ identity used : sin (A-B)= sin A . cosB - cosA . sinB]

(iii) cos 60° cos 30° + sin 60° sin 30°

= cos(60⁰-30⁰)

= cos30⁰

= √3/2

[ identity used : cos(A-B) = cosA . cosB +sinA . sinB]

Answer 2

Answer:

(ii) sin 60° cos 30° - cos 60° sin 30° = 1

(iii) cos 60° cos 30° + sin 60° sin 30° = ?

Step-by-step explanation:

(ii) sin 60° cos 30° - cos 60° sin 30° = 1

⇒ $\frac{3}{2} * \sqrt{\frac{3}{2} } - \frac{1}{2} * \frac{1}{2}$

$\frac{3}{4} - \frac{1}{4}$

$\frac{2}{4} = \frac{1}{2}$

(iii) cos 60° cos 30° + sin 60° sin 30° = ?

⇒  sorry

     Hope It Helps You