(ii) sin A (1 + tan A) + cos A (1 + cot A) = sec A+ cosec A
Answers
Answered by
3
Answer:
Your answer attached in the photo
Attachments:
Answered by
0
Answer:
LHS =1+cotA−cosecA=1+
sinA
ccos- sinA
1 =
sinA
(sinA+cosA−1)
1+tanA+secA=1+
cosA
sinA
+
cosA
1
=
cosA
(sinA+cosA+1)
(1+cotA−cosecA)(1+tanA+secA)
=
sinAcosA
(sinA+cosA−1)(sinA+cosA+1)
=
sinAcosA
(sinA+cosA)
2
−1
=
sinAcosA
1+2sinAcosA−1
=2=RHS
Hence Proved
Similar questions