Question

(ii) sin(tan^-1 x) defrantiat ​

Answer 1

Step-by-step explanation:

We have,

$y = \sin( \tan^{- 1} (x) )$

$\frac{dy}{ dx} = \cos( \tan ^{ - 1} (x) ) . \frac{1}{1 + {x}^{2} }$