Question

ii) Solve quadratic equation by using formula method
x²+x+5=0
Solution: x² + x + 5 = 0 comparing with
ax? + bx + c = 0
we get, a = 1,
b=
I c=5
: b2 - 4ac = (1)2 - 4x1x5
=1-20
=
± √b² - 4ac
X=
2a
-11-19
=
2x1
-11-19
But 1-19 is not a real number. Hence,
roots of the equation are not real.
til Writ
1​

Answer 1

Answer:

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