Question

ii) Solve the quadratic equation using formula
x²-3x - 2 = 0​

Answer 1

Answer:

$x = \frac{3 + \sqrt{17} }{2} \: or \: x = \frac{3 - \sqrt{17} }{2}$

Step-by-step explanation:

Given,

$x {}^{2} - 3x - 2 = 0 \\ arrenging \: it \: in \: standered \: form \\ 1x {}^{2} - 3x - 2 = 0 \\ therefore \: by \: quadratic \: formula \: \\x = \frac{ - b + - \sqrt{b {}^{2} - 4ac } }{2a} \\ = \frac{ - ( - 3) + - \sqrt{( - 3) {}^{2} - 4(1)( - 2) } }{2(1)} \\ = \frac{ 3 + - \sqrt{( - 3) {}^{2} + 8} }{2} \\ = \frac{3 + - \sqrt{9 + 8} }{2} \\ = \frac{3 + - \sqrt{17} }{2} \\ therefore \: x = \frac{3 + \sqrt{17} }{2} \: or \: x = \frac{3 - \sqrt{17} }{2}$

Hope this will help you!!