Physics, asked by drjrs100, 5 months ago

(ii) Starting from rest, a body of mass 100 Kg attains velocity of 40 m/sec in 10 sec. find
the force acting on the body.​

Answers

Answered by BrainlyTwinklingstar
28

Given :

Initial velocity = zero

Mass of the body = 100kg

Final velocity = 40m/s

Time taken = 10sec

To find :

The force acting on the body.

Solution :

Firstly we have to find acceleration of the body, as we are provided with initial velocity, final velocity and time taken we can use first equation of motion that is,

v = u + at

where,

  • v denotes final velocity
  • u denotes Initial velocity
  • a denotes acceleration
  • t denotes time

by substituting all the given values in the equation,

➝ v = u + at

➝ 40 = 0 + (a)(10)

➝ 40 = 10a

➝ a = 40/10

➝ a = 4m/s²

Now, using second law of motion that is,

The rate of change of linear momentum of a body with time is proportional to the net external force acting on it .i.e.,

F = ma

where,

  • F denotes force
  • m denotes mass
  • a denotes acceleration

by substituting the given values in the equation,

➝ F = ma

➝ F = (100)(4)

➝ F = 400N.

thus, the force acting on the body is 400N.

Remember !

SI unit of froce is Newton (N).

SI unit of acceleration is metre per second square (m/s²).

Answered by sujalchand2211
3

Answer:

Given :

Initial velocity = zero

Mass of the body = 100kg

Final velocity = 40m/s

Time taken = 10sec

To find :

The force acting on the body.

Solution :

Firstly we have to find acceleration of the body, as we are provided with initial velocity, final velocity and time taken we can use first equation of motion that is,

v = u + at

where,

v denotes final velocity

u denotes Initial velocity

a denotes acceleration

t denotes time

by substituting all the given values in the equation,

➝ v = u + at

➝ 40 = 0 + (a)(10)

➝ 40 = 10a

➝ a = 40/10

➝ a = 4m/s²

Now, using second law of motion that is,

The rate of change of linear momentum of a body with time is proportional to the net external force acting on it .i.e.,

F = ma

where,

F denotes force

m denotes mass

a denotes acceleration

by substituting the given values in the equation,

➝ F = ma

➝ F = (100)(4)

➝ F = 400N..

thus, the force acting on the body is 400N.

Remember !

SI unit of froce is Newton (N).

SI unit of acceleration is metre per second square (m/s²).

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