Question

ii) State the formula for moment of
inertia of ring about transverse axis
perpendicular to the plane.

Answer 1

Explanation:

Moment of Inertia of ring about an axis perpendicular to its plane is I=MR

2

By perpendicular axis theorem , moment of Inertia about any diameter I

′

=

2

I

=

2

MR

2

Moment of Inertia about any tangent is

I

1

=I

′

+MR

2

=

2

MR

2

+MR

2

=

2

3MR

2

=

2

3I

Answer 2

Expression for the Moment of Inertia of an Annular Ring:

dI = 2 π t ρ r³ . dr . Where M is the total mass of the annular ring. This is an expression for moment of inertia of annular ring about a transverse axis passing through its centre.