Math, asked by anmolaeron75, 6 months ago

II. Sum of the areas of two squares is 468 m. If the difference of their perimeters is 24 m.
find the sides of the two squares.

Answers

Answered by puneetkk

0

Step-by-step explanation:

use two equation to solve...

x² + y² = 468

where x and y are sides of two squares

also

4(x-y)= 24

use these two equation and solve them...you will get your answer..

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